5x^2+bx+20=20

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Solution for 5x^2+bx+20=20 equation:


Simplifying
5x2 + bx + 20 = 20

Reorder the terms:
20 + bx + 5x2 = 20

Add '-20' to each side of the equation.
20 + bx + -20 + 5x2 = 20 + -20

Reorder the terms:
20 + -20 + bx + 5x2 = 20 + -20

Combine like terms: 20 + -20 = 0
0 + bx + 5x2 = 20 + -20
bx + 5x2 = 20 + -20

Combine like terms: 20 + -20 = 0
bx + 5x2 = 0

Solving
bx + 5x2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5x2' to each side of the equation.
bx + 5x2 + -5x2 = 0 + -5x2

Combine like terms: 5x2 + -5x2 = 0
bx + 0 = 0 + -5x2
bx = 0 + -5x2
Remove the zero:
bx = -5x2

Divide each side by 'x'.
b = -5x

Simplifying
b = -5x

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